> He said he could make the pricing work at half what reddit is asking, for $1.26/mo base API cost.
He said a much more reasonable thing would be to cut the price in half and give a 3 month transition period to make it "feasible for more developers, myself included."
> However in a perfect world I think lowering the price by half and providing a three month transition period to the paid API would make the transition feasible for more developers, myself included. These concessions seem minor and reasonable in the face of the changes.
What that would likely mean is removing as many API calls as possible and removing features as a result. Which means fewer users would want to pay for it.
> I was just spitballing that doubling his revenue would mean he could manage the price Reddit is asking (since he said he could make due with half).
Also, as a tidbit. His current subscription pricing is $5/mo for ultra.
If we want to take that as his revenue for an ongoing subscription to double (since API access is going to be monthly), then the app would be $10/mo or $120/yr.
He said a much more reasonable thing would be to cut the price in half and give a 3 month transition period to make it "feasible for more developers, myself included."
> However in a perfect world I think lowering the price by half and providing a three month transition period to the paid API would make the transition feasible for more developers, myself included. These concessions seem minor and reasonable in the face of the changes.
What that would likely mean is removing as many API calls as possible and removing features as a result. Which means fewer users would want to pay for it.
> I was just spitballing that doubling his revenue would mean he could manage the price Reddit is asking (since he said he could make due with half).
Also, as a tidbit. His current subscription pricing is $5/mo for ultra.
If we want to take that as his revenue for an ongoing subscription to double (since API access is going to be monthly), then the app would be $10/mo or $120/yr.
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